! Copyright (c) 2010 Aaron Schaefer. ! See https://factorcode.org/license.txt for BSD license. USING: arrays combinators.short-circuit kernel math math.combinatorics math.functions math.primes project-euler.common sequences sequences.extras ; FROM: project-euler.common => permutations? ; IN: project-euler.070 ! https://projecteuler.net/problem=70 ! DESCRIPTION ! ----------- ! Euler's Totient function, φ(n) [sometimes called the phi ! function], is used to determine the number of positive numbers ! less than or equal to n which are relatively prime to n. For ! example, as 1, 2, 4, 5, 7, and 8, are all less than nine and ! relatively prime to nine, φ(9)=6. The number 1 is considered ! to be relatively prime to every positive number, so φ(1)=1. ! Interestingly, φ(87109)=79180, and it can be seen that 87109 ! is a permutation of 79180. ! Find the value of n, 1 < n < 10^(7), for which φ(n) is a ! permutation of n and the ratio n/φ(n) produces a minimum. ! SOLUTION ! -------- ! For n/φ(n) to be minimised, φ(n) must be as close to n as ! possible; that is, we want to maximize φ(n). The minimal ! solution for n/φ(n) would be if n was prime giving n/(n-1) but ! since n-1 never is a permutation of n it cannot be prime. ! The next best thing would be if n only consisted of 2 prime ! factors close to (in this case) sqrt(10000000). Hence n = ! p1*p2 and we only need to search through a list of known prime ! pairs. In addition: ! φ(p1*p2) = p1*p2*(1-1/p1)(1-1/p2) = (p1-1)(p2-1) ! ...so we can compute φ(n) more efficiently. integer 1000 [ - ] [ + ] 2bi primes-between ; inline : n-and-phi ( seq -- seq' ) ! ( seq = { p1, p2 } -- seq' = { n, φ(n) } ) [ product ] [ [ 1 - ] map product ] bi 2array ; : fit-requirements? ( seq -- ? ) first2 { [ drop 7 10^ < ] [ permutations? ] } 2&& ; : minimum-ratio ( seq -- n ) [ [ first2 / ] map arg-min ] keep nth first ; PRIVATE> : euler070 ( -- answer ) likely-prime-factors 2 all-combinations [ n-and-phi ] map [ fit-requirements? ] filter minimum-ratio ; ! [ euler070 ] 100 ave-time ! 379 ms ave run time - 1.15 SD (100 trials) SOLUTION: euler070